1.Find the perimeter of a quadrilateral with vertices at C (−1, 1), D (3, 4), E (6, 0), F (2, −3). Round your answer to the nearest hundredth when necessary. 12 units 16 units 20 units 24 units
Any ideas ?
Nope
What about distance formula ?
The distance formula
Yes. The distance between two points \(\large{(x_1,y_1)~\text{and}~(x_2,y_2)}\) is given by: \[\large{\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\]
D= square root (x2-x1)^2 +(y2-y1)^2
Yup
I kinda forgot how to slove it Can u help me @vishweshshrimali5
Okay lets see. For calculating perimeters calculate: CD, DE, EF, FC using distance formula and then add all of these lengths to get the perimeter
I am going to show how you can find out CD. 1. For calculating CD, apply distance formula for coordinates of vertices C and D. 2. \(\large{CD = \sqrt{(3-(-1))^2 + (4-1)^2}}\) Any doubt in any step ?
Nope
CD = 5 DE= 7.07 EF= 5 FC = 5
Right @vishweshshrimali5
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