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Mathematics 20 Online
OpenStudy (anonymous):

1.Find the perimeter of a quadrilateral with vertices at C (−1, 1), D (3, 4), E (6, 0), F (2, −3). Round your answer to the nearest hundredth when necessary. 12 units 16 units 20 units 24 units

OpenStudy (vishweshshrimali5):

Any ideas ?

OpenStudy (anonymous):

Nope

OpenStudy (vishweshshrimali5):

What about distance formula ?

OpenStudy (anonymous):

The distance formula

OpenStudy (vishweshshrimali5):

Yes. The distance between two points \(\large{(x_1,y_1)~\text{and}~(x_2,y_2)}\) is given by: \[\large{\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\]

OpenStudy (anonymous):

D= square root (x2-x1)^2 +(y2-y1)^2

OpenStudy (vishweshshrimali5):

Yup

OpenStudy (anonymous):

I kinda forgot how to slove it Can u help me @vishweshshrimali5

OpenStudy (vishweshshrimali5):

Okay lets see. For calculating perimeters calculate: CD, DE, EF, FC using distance formula and then add all of these lengths to get the perimeter

OpenStudy (vishweshshrimali5):

I am going to show how you can find out CD. 1. For calculating CD, apply distance formula for coordinates of vertices C and D. 2. \(\large{CD = \sqrt{(3-(-1))^2 + (4-1)^2}}\) Any doubt in any step ?

OpenStudy (anonymous):

Nope

OpenStudy (anonymous):

CD = 5 DE= 7.07 EF= 5 FC = 5

OpenStudy (anonymous):

Right @vishweshshrimali5

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