Simplify: (1 point)
simplify what?
\[4\sqrt{2}+7\sqrt{2}-3\sqrt{2}\]
Since all the radicands are a 2, you can add or subtract like "normal" the 4 andd 7 and 3. 4+7-3=8 so your answer is \[8\sqrt{2}\]
thank you can you help me with more please
@IMStuck
of course!
what else did you need help with?
\[3\sqrt{10}+7\sqrt{15}-6\sqrt{10}-4\sqrt{15}\]
its simplifying too
ok here you combine the radicands 15 together, and then the radicands of 10 together. \[3\sqrt{10}-6\sqrt{10}=-3\sqrt{10}\]and do the same with the sqrt 15:\[7\sqrt{15}-4\sqrt{15}=3\sqrt{15}\]
The answer is \[3\sqrt{15}-3\sqrt{10}\]
thank you!! so theres one question where all the numbers are different this time can you show me how to do that one
yep!
\[7\sqrt{3}-4\sqrt{6}+\sqrt{48}-\]
\[-\]\[\sqrt{54}\]
ok the radicands 3 and 6 are simple enough as they are, you cannot get them to simplify any further. However, the 48 and the 54 each have a hidden perfect square in them. 48 is equal to 16*3 (16 is a perfect square) and 54 is 9*6 (9 is a perfect square. So let's rewrite:
\[7\sqrt{3}-4\sqrt{6}+\sqrt{16*3}-\sqrt{9*6}\]which simplifies to\[7\sqrt{3}-4\sqrt{6}+4\sqrt{3}-3\sqrt{6}\]
see now the radicands are either 3's or 6's. So they can be combined like this:\[7\sqrt{3}+4\sqrt{3}=11\sqrt{3}\]and\[-4\sqrt{6}-3\sqrt{6}=-7\sqrt{6}\]
The final answer is\[11\sqrt{3}-7\sqrt{6}\]
The idea with these is always the same...try to get the radicands to simplify into something you can combine other radicands with. That's what simplifying is all about.
ohhhhhhhhh I get it thank you so much, you really helped me!
You're welcome! I'm glad to help!
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