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Mathematics 8 Online
OpenStudy (zab505):

Need Help!

OpenStudy (zab505):

OpenStudy (anonymous):

A you'd want to multiply by 1- sec x to get 1-sec^2 x in the bottom, which than equals -tan^2x based on pythagorean identities

OpenStudy (anonymous):

tan^2 x + sec^2 x = 1

OpenStudy (anonymous):

*tan^2x

OpenStudy (zab505):

Can you help me with one more?

OpenStudy (anonymous):

Sure

OpenStudy (zab505):

True or False?

OpenStudy (anonymous):

What do you think ?

OpenStudy (zab505):

I think false.

OpenStudy (anonymous):

yes it's false

OpenStudy (anonymous):

Identity equations are true no matter what value it is plugged in.

OpenStudy (zab505):

Can you help me with another question?

OpenStudy (anonymous):

yes sure

OpenStudy (zab505):

Which of the following equations are identities? Check all that apply. A. cot2x + csc2x = 1 B. sin2x - cos2x = 1 C. sin2x = 1 - cos2x D. tan2x = sec2x - 1

OpenStudy (anonymous):

1+cot^2 x = csc^2x sin^2x + cos^2x = 1 1 + tan^2x = sec^2 x those are the 3 trig identities. Can you eliminate some answers?

OpenStudy (zab505):

Wait C and D?

OpenStudy (anonymous):

Yes those are correct! :)

OpenStudy (zab505):

Wow can you help me with another?

OpenStudy (anonymous):

yes sure

OpenStudy (zab505):

The expression cosx + tanx sinx can be simplified to _____. A. cscx B. secx C. cotx D. cosx sinx

OpenStudy (anonymous):

hint: \[\tan x = \frac{ \sin x }{ \cos x}\] So if you have \[\cos x + \frac{ \sin x }{ \cos x } (sinx)\] Now you have : \[\cos x + \frac{ \sin ^{2} x}{ \cos x }\] Can you continue the problem? Lemme know if you need more hints

OpenStudy (zab505):

Would it be B?

OpenStudy (anonymous):

Yes!

OpenStudy (zab505):

Wow haha, can you help me with another one?

OpenStudy (anonymous):

Sure

OpenStudy (zab505):

OpenStudy (anonymous):

csc x = 1/sinx sec x = 1/cos x tan x = 1/cot x cot x = 1/ tan x Eliminate some answers?

OpenStudy (anonymous):

cot = 1 / tan since tan = sin/cos cot = cos /sin

OpenStudy (zab505):

would csc x=1/sinx be correct?

OpenStudy (anonymous):

yes

OpenStudy (zab505):

And tan=sin/cos the other?

OpenStudy (anonymous):

Yes, tan = sin/cos

OpenStudy (zab505):

So what would that translate to in answers?

OpenStudy (anonymous):

Answer is C and D c. cot = cos / sin because tan = sin/cos , and cot = 1/tan then cot = 1/ (sin/cos), which just means you flip the fraction. Thus, cot = cos /sin, check! d. tan = 1/cot

OpenStudy (anonymous):

do you get d?

OpenStudy (zab505):

yeah, can you help me with another

OpenStudy (zab505):

one?

OpenStudy (anonymous):

yes

OpenStudy (zab505):

All identities are equations, and all equations are identities. True or False?

OpenStudy (anonymous):

remember that sin x = pi is not an identity , but it is an equation. So what do you think the answer is?

OpenStudy (zab505):

False! Can you help me with another one?

OpenStudy (anonymous):

Yes and yes :)

OpenStudy (zab505):

OpenStudy (anonymous):

Yes, according to the cofunction identities, memorizing them would be faster.

OpenStudy (anonymous):

true that is

OpenStudy (zab505):

Wow, can you help me with another one I'm learning better with you than with teacher

OpenStudy (anonymous):

sure, and I'm no where as good haha. Just 1 on 1 is easier to communicate :)

OpenStudy (zab505):

OpenStudy (zab505):

When do you get on? Thank you so much I have to leave, but will get on in one hour.

OpenStudy (anonymous):

are you allowed to use calculator? and I get on around 1- 4:30 pm in California time. pacific coast

OpenStudy (anonymous):

OpenStudy (anonymous):

Lemme know if you need the next hint

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