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OpenStudy (zab505):
OpenStudy (anonymous):
A
you'd want to multiply by 1- sec x to get 1-sec^2 x in the bottom, which than equals
-tan^2x based on pythagorean identities
OpenStudy (anonymous):
tan^2 x + sec^2 x = 1
OpenStudy (anonymous):
*tan^2x
OpenStudy (zab505):
Can you help me with one more?
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OpenStudy (anonymous):
Sure
OpenStudy (zab505):
True or False?
OpenStudy (anonymous):
What do you think ?
OpenStudy (zab505):
I think false.
OpenStudy (anonymous):
yes it's false
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OpenStudy (anonymous):
Identity equations are true no matter what value it is plugged in.
OpenStudy (zab505):
Can you help me with another question?
OpenStudy (anonymous):
yes sure
OpenStudy (zab505):
Which of the following equations are identities? Check all that apply.
A. cot2x + csc2x = 1
B. sin2x - cos2x = 1
C. sin2x = 1 - cos2x
D. tan2x = sec2x - 1
OpenStudy (anonymous):
1+cot^2 x = csc^2x
sin^2x + cos^2x = 1
1 + tan^2x = sec^2 x
those are the 3 trig identities. Can you eliminate some answers?
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OpenStudy (zab505):
Wait C and D?
OpenStudy (anonymous):
Yes those are correct! :)
OpenStudy (zab505):
Wow can you help me with another?
OpenStudy (anonymous):
yes sure
OpenStudy (zab505):
The expression cosx + tanx sinx can be simplified to _____.
A. cscx
B. secx
C. cotx
D. cosx sinx
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OpenStudy (anonymous):
hint:
\[\tan x = \frac{ \sin x }{ \cos x}\]
So if you have
\[\cos x + \frac{ \sin x }{ \cos x } (sinx)\]
Now you have :
\[\cos x + \frac{ \sin ^{2} x}{ \cos x }\]
Can you continue the problem? Lemme know if you need more hints
OpenStudy (zab505):
Would it be B?
OpenStudy (anonymous):
Yes!
OpenStudy (zab505):
Wow haha, can you help me with another one?
OpenStudy (anonymous):
Sure
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OpenStudy (zab505):
OpenStudy (anonymous):
csc x = 1/sinx
sec x = 1/cos x
tan x = 1/cot x
cot x = 1/ tan x
Eliminate some answers?
OpenStudy (anonymous):
cot = 1 / tan
since tan = sin/cos
cot = cos /sin
OpenStudy (zab505):
would csc x=1/sinx be correct?
OpenStudy (anonymous):
yes
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OpenStudy (zab505):
And tan=sin/cos the other?
OpenStudy (anonymous):
Yes, tan = sin/cos
OpenStudy (zab505):
So what would that translate to in answers?
OpenStudy (anonymous):
Answer is C and D
c. cot = cos / sin
because tan = sin/cos , and cot = 1/tan
then cot = 1/ (sin/cos), which just means you flip the fraction. Thus,
cot = cos /sin, check!
d. tan = 1/cot
OpenStudy (anonymous):
do you get d?
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OpenStudy (zab505):
yeah, can you help me with another
OpenStudy (zab505):
one?
OpenStudy (anonymous):
yes
OpenStudy (zab505):
All identities are equations, and all equations are identities. True or False?
OpenStudy (anonymous):
remember that sin x = pi is not an identity , but it is an equation. So what do you think the answer is?
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OpenStudy (zab505):
False! Can you help me with another one?
OpenStudy (anonymous):
Yes and yes :)
OpenStudy (zab505):
OpenStudy (anonymous):
Yes, according to the cofunction identities, memorizing them would be faster.
OpenStudy (anonymous):
true that is
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OpenStudy (zab505):
Wow, can you help me with another one I'm learning better with you than with teacher
OpenStudy (anonymous):
sure, and I'm no where as good haha. Just 1 on 1 is easier to communicate :)
OpenStudy (zab505):
OpenStudy (zab505):
When do you get on? Thank you so much I have to leave, but will get on in one hour.
OpenStudy (anonymous):
are you allowed to use calculator?
and I get on around 1- 4:30 pm in California time. pacific coast
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