Question

Write an equation in slope-intercept form of the line that passes through (– 5, 4) and is parallel to the graph of y = -4x + 1

Answer 1

hmmm what's the slope of \(\bf y = -4x + 1\) anyway?

Answer 2

Lol this was the exact problem given to me to solve, i dont know

Answer 3

\(\bf \large y = {\color{brown}{ -4}}x + 1\) see the slope now? what do you think it's?

Answer 4

oh lmao thats what you were asking, i thought you were telling me something was missing

Answer 5

yes i know what the slope is, and b is 1

Answer 6

b is the y-intercept. In y=mx+b, the slope is m

Answer 7

oh so the points are (-5, 4) and (4, 1)?

Answer 8

nope (4,1) is not a point

Answer 9

lol if i can just get a full asnwer i can understand it, i am not looking for answers, i am looking to understand

Answer 10

so... .what do you think is the slope?

Answer 11

ohhhh its 4/1?

Answer 12

well.. notice the negative in front of it \(\bf \bf \large y = {\color{brown}{ -4}}x + 1\)

Answer 13

oh yeah lol

Answer 14

-4/1

Answer 15

so a slope parallel to that one
will have the same slope as that one

so now we know the parallel line will have a slope of -4 and passes through (-5, 4)
thus
\(\bf \begin{array}{lllll}
&x_1&y_1\\
&({\color{red}{ -5}}\quad ,&{\color{blue}{ 4}})\quad
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= -4
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 16

y - 4 = -4 (x + 5)
y - 4 = -4x + 5
Add 4 on both sides
Y = -4x + 9?

Answer 17

oh my bad wait

Answer 18

y - 4 = -4x -20
Add 4 on both sides
y = -4x - 16