Question

Need Help!

Answer 1

hint: check out

http://www.purplemath.com/modules/idents.htm

Answer 2

@zzr0ck3r

Answer 3

I agree with @jim_thompson5910

Answer 4

I did

Answer 5

do you see the identity where it lists tan(x/2) ?

Answer 6

I belief so

Answer 7

if sin(x) = -3/5 and we're in Q3, what is cos(x) ?

Answer 8

not sure

Answer 9

use the idea that sin^2 + cos^2 = 1

Answer 10

Sorry I'm so lost

Answer 11

sin^2 + cos^2 = 1

(-3/5)^2 + z^2 = 1

solve for z

Answer 12

+,-4/5

Answer 13

we're in Q3, so is cosine positive or negative?

Answer 14

Negative

Answer 15

that means

sin(x) = -3/5
cos(x) = -4/5

Answer 16

plug those into the tan(x/2) formula and simplify

Answer 17

How?

Answer 18

\[\Large \tan \left(\frac{x}{2}\right) = \frac{1-\cos(x)}{\sin(x)}\]


\[\Large \tan \left(\frac{x}{2}\right) = \frac{1-\left(-\frac{4}{5}\right)}{-\frac{3}{5}}\]


\[\Large \tan \left(\frac{x}{2}\right) = ???\]

Answer 19

x=-2.49 and -4.39

Answer 20

idk how you're getting that

Answer 21

and you're supposed to get one answer only

Answer 22

tan(1/2x)

Answer 23

All you're doing at this point is simplifying

\[\Large \frac{1-\left(-\frac{4}{5}\right)}{-\frac{3}{5}}\]

Answer 24

Just forget it

Answer 25

\[\Large \frac{1-\left(-\frac{4}{5}\right)}{-\frac{3}{5}}\]

\[\Large \frac{\frac{5}{5}+\frac{4}{5}}{-\frac{3}{5}}\]

\[\Large \frac{\frac{5+4}{5}}{-\frac{3}{5}}\]

\[\Large \frac{\frac{9}{5}}{-\frac{3}{5}}\]


what's next?

Answer 26

-3! I'm so sorry for everything.

Answer 27

that's ok