HELP I AM BEGGING YOU I WILL GIVE YOU A MEDAL/FAN!!! Which logarithmic graph can be used to approximate the value of y in the equation 4y = 8? I honestly don't know where to even start.
@phi
anyone?
Well I can help you out.
Lets see, your equation is this : \[\large{4y = 8}\] Right ?
sorry I typed it wrong, it's \[4^{y}= 8\]
Okay
\[\large{4^y = 8}\] Lets take log both sides
that would be log( base 4) 4^y = log(base 4) 8
we will get: \[\large{\log(4^y) = \log 8}\] \[\large{\implies y \log 4 = \log 8}\] Yes
That's the part where I get stuck. I'm not really sure what to do after.
Now, \[\large{\log_4(4) = 1}\]
I have a doubt in my mind: The graphs are for what base? log base 4 or any other base ?
I think it Is log base 4
Was it given in the question ?
Because log 0 for whatever base is not defined but both graphs have show some value for it.
@ikram002p Can you check the graphs please ?
in the lesson, it said to take the log of whatever is the base; it said to take the log of 4
Well I am not sure that the graphs are correct :( Can you wait till someone checks it ? @ganeshie8
don't you have any x on the expression?
here is the work I did to get the second choice, but im not sure if it is right; 4^y = x log (base 4) 4^y = log (base 4) x y = log (base 4) x From there I graphed the logarithm
the graph of y =\(log_4 8\) is a horizontal line; it's not any of them
the value 8 is plugged in for x, so I think it would actually be \[y=\log _{4} x\]
so, the second one is the right answer
Reason, when x =8 , y = 1.5
thank you :) that's what I thought but I wasn't quite sure
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