Question

help will fan and medal guid me plzzz


Perform the operation.

https://crookcountysd.owschools.com/media/g_alg01_2013/10/584.gif

Answer 1

the first step is to factor all the equations

Answer 2

do you know how to do that?

Answer 3

no

Answer 4

okay, i'll explain then

Answer 5

ok

Answer 6

in this equation you first have to factor each equation individually before you can look at the big picture. So we're first going to look at
\[k ^{2}+9k-10\]
In order to factor that equation you look at the last sign on the 10, which is a minus. Because of this we know that one of the variables is going to be positive and the other is going to be negative. So the new equation would look like this
\[(k-?)(k+?)\]
In order to factor you need to think of the two numbers that multiply to get 10 but add to get 9. Can you try to find that?

Answer 7

it's okay if you can't get it at first, just tell me if you get stuck

Answer 8

no i cant get it

Answer 9

That's okay. The new equation is now going to be
\[(k-1)(k+10)\]because (10)+(-1)=9 and 10 times -1 is -10.
So now we're going to factor the bottom on the right equation. so
\[(k-1)^{2}\] becomes \[(k-1)(k+1)\] because by multiplying 1 by -1 we get a negative 1.

Answer 10

So on this problem what do you want to solve for? The variable k?

Answer 11

or just a simplified version of the problem?

Answer 12

@sara45 ?

Answer 13

um... idk

Answer 14

we'll do both then

Answer 15

ok

Answer 16

After we factor the problem completely it becomes \[\frac{ (k-1)(k+10) }{ 34 }\times \frac{ 2 }{ (k-1)(k+1) }\] You can then simplify the problem by canceling out the (k-1)s and crossing out the 2 and making the 34 a 17. The new problem would look like this \[\frac{ (k+10) }{ 17 }\times \frac{ 1 }{ (k+1) }\] once you actually multiply it it comes out as \[\frac{ (k+10) }{ (17k+17) }\]if you just wanted the multiplication that'd be your answer. Now i'm going to solve for k

Answer 17

okay so in this problem you'd put that equation equal to zero. and if I solve the problem that is actually a really weird answer. So I'm guessing all the problem is asking for is that equation up there, unless you had actual multiple choice answers or you're working on a different unit.

Answer 18

multi question

Answer 19

okay what are the choices?

Answer 20

\[k \le3 k \ge3 k \le-3 k \ge-3\]

Answer 21

spases in the 3 and k

Answer 22

okay hold on

Answer 23

it's the first one

Answer 24

\[k \le 3\]

Answer 25

yes, that's what I got