Question

A dog at point A goes in pursuit of a fox 30 metres away. The dog takes a leap of 2 m against 1m long leaps of the fox. If the dog makes two leaps to the fox’s three, at what distance from A will the dog catch up with the fox?

Answer 1

30/2=15

Answer 2

2-1=1

Answer 3

2x=3 so x=3/2

Answer 4

afox has already covered 30 meters so 30/1 =30 for fox and 30/2=15

Answer 5

Each leap of the dog is 2 m.
Each leap of the fox is 1 m.

If the dog makes two leaps to the fox’s three.

This means that each time the dog advances 4 m, the fox advances 3 m.

Answer 6

so distance covered by dog=1/60

Answer 7

Each 4 m of the dog movement, the dog is 1 m closer.
The dog has to get 30 m closer.
How many 4 m advances must the dog make to be 30 m closer?

Answer 8

30/4=15/2

Answer 9

in 15 leaps the dog would the distance 30meters

Answer 10

When the dog advances 4 m, it's 1 m closer.
When the dog advances 2*4 m, it's 2*1 m closer.
When the dog advances 3*4 m, it's 3*1 m closer.
When the dog advances 4*4 m, it's 4*1 m closer.
etc.
When the dog advances ___*4 m, it's 30*1 m closer.

What goes in the blank?

Answer 11

120m

Answer 12

Correct.
Since each 4 m of the dog means catching up 1 m, it takes 30 * 4m of the dog advancing to catch up all 30 m.
30 * 4m = 120 m.
That is it.

Answer 13

hmmmmmmmmmm..

Answer 14

Did you post a problem about two runners running around a circular track?

Answer 15

yes

Answer 16

Oh, I see that it was answered already.