Question

HELP !!!!!!!!???????!!!!!!!!!!!!

Answer 1

\[\frac{ 3x^2-8 }{ 2x }\] for x=2

Answer 2

Plug in 2 for each x and evaluate the fraction.

Answer 3

so it would be written \[\frac{ 3*2^2-8 }{ 2*2 }\]

Answer 4

right.

Answer 5

okay so it would be \[\frac{ 6^2-8 }{ 4 }\] right ?

Answer 6

No, remember order of operations means you would do the exponent first:
\[\frac{3(2^2)-8}{4}\rightarrow \frac{3(4)-8}{4} \]

Answer 7

oh okay so \[\frac{ 12-8 }{ 4 }\rightarrow \frac{ 4 }{ 4 }=1\] right ?

Answer 8

right!

Answer 9

okay

Answer 10

thank u