Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

Evaluate the determinant.

OpenStudy (anonymous):

\[\left| \frac{ \frac{ 1 }{ 6 } }{ \frac{ -6 }{ 5 } } \frac{ \frac{ 1 }{ 8 } }{ \frac{ 10 }{ 7 } }\right|\] sorriees I have no idea how to solve this...please explain?

OpenStudy (anonymous):

this doesn't look right... :D

OpenStudy (anonymous):

\[\large \left|\begin{matrix}\frac16 &\frac13\\\frac{-6}5&\frac{10}7\end{matrix}\right|\]

OpenStudy (anonymous):

oops lol yes...sorryyy /.\

OpenStudy (anonymous):

Or was it 1/8? \[\large \left|\begin{matrix}\frac16 &\frac1{\color{red}8}\\\frac{-6}5&\frac{10}7\end{matrix}\right|\]

OpenStudy (anonymous):

I obviously need to work on my checking skills, its 1/8

OpenStudy (agreene):

remember that to do determinants you multiply horizontally in the form: \[A=\left[\begin{matrix}a & b \\ c & d\end{matrix}\right]\] \[A=ad-cb\]

OpenStudy (anonymous):

What he said ^

OpenStudy (anonymous):

So it's just \[\frac{ 1 }{ 8 } x \frac{ -6 }{ 5 }\] and \[\frac{ 1 }{ 6 } \times \frac{ 10 }{ 7 }\] ? but don't I need a common denominator first?

OpenStudy (anonymous):

you can just multiply them out straight away.... common denominators are for wusses (and for adding and subtracting HAHA)

OpenStudy (anonymous):

I multiply fractions horizontally, correct? Lol I haven't done this in forever so I'm lost

OpenStudy (anonymous):

yes, horizontally haha

OpenStudy (anonymous):

\[-\frac{ 6 }{ 40 } - \frac{ 10 }{ 42 }\]

OpenStudy (anonymous):

o.o did I mess up

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!