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Mathematics 7 Online
OpenStudy (armyrangers):

Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of sin x° and cos y° share?

OpenStudy (armyrangers):

OpenStudy (armyrangers):

@tester97

OpenStudy (armyrangers):

@Compassionate

OpenStudy (armyrangers):

@Gir_lover_♥

OpenStudy (gir_lover_♥):

@Venny

OpenStudy (anonymous):

Oh yes this is a right triangle. Sin=opposite/hypotenuse so we have to use Pythagorean theorem to solve for c \(c^2=15^2+8^2\) can you solve for c first?

OpenStudy (armyrangers):

what would that be

OpenStudy (love.kat123):

its a picture of a triangle !!!! 0-0 umm.......... yup

OpenStudy (anonymous):

Forgive me I am wrong again I haven't done this in a while. I assumed it was different. We still need to find \(c^2=225+64\) which is the same as \(c^2=289\) \(c=\sqrt{289}=17\) so now we find the Sin of x which is opposite/hypotenuse. which is the same as \(\frac{8}{17}\)

OpenStudy (anonymous):

Next we find the cos of y which is adjacent/hypoteneuse. cos(y)=\(\frac{8}{17}\) this means that the sin(x) and the cos(y) are the same

OpenStudy (armyrangers):

@Venny would it be .0199

OpenStudy (anonymous):

Sorry I messed up before, I assumed it was a special triangle and I shouldn't have

OpenStudy (love.kat123):

ur smart i shall friend u venny^ and im sorry i cant help armyrangers

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