Question

@pgpilot326

Answer 1

\[\sqrt[3]{\frac{ 1 }{ x ^{-6} }}\]

Answer 2

thats a 3 and -6 if you cant see it

Answer 3

\[\sqrt[3]{x ^{-6}}\]

Answer 4

then divide -6 by 3?

Answer 5

\[\sqrt[3]{\frac{ 1 }{ x^{-6} }}=\sqrt[3]{x^6}=\large{x^{\frac{ 6 }{ 3 }}}=x^2\]

Answer 6

when you put the negative exponent as the numorator is becomes positive?

Answer 7

yes... \[x^{-n}=\frac{ 1 }{ x^n } \text{ and } \frac{ 1 }{ x^{-n} }=x^n\]

Answer 8

ahh alright thanks

Answer 9

@jagr2713 i think this was simpler than how krop explained it to you and he got the same answer

Answer 10

yea thx

Answer 11

you're welcome thanks @pgpilot326 for helping

Answer 12

do you understand why \[x^{-n} = \frac{ 1 }{ x^n }\]

Answer 13

i dont understand why is it because exponents can't be negative?

Answer 14

can you fill this in?