Question:
I believe in ye @paki , you can explain it :P
sorry man, no idea... confused...
SAME :) anyways thanks for the try.
@SolomonZelman please help here... and pleasure....
To answer your question. Why can't we guarantee that?
Well to be honest, I did not even understand the question.
when it say n*2 or n*3, and if n>1 does it mean 2*2=4 blocks or 6 blocks etc...
and is green and red in form of checkerboard or any arrangements?
Well, it says that all corners have to be of either color, so we can't guarantee anything. I would guarantee that there is a square of such a size when n is 1.5 or less.
1.5 is not even discrete. o.O
and it says 4 corners, WT*
it is not an integer, but we can't have 1 square of 2 colors right? and then we certainly can't guarantee.
its say n>1 why is that?
lets say n*2 = 1*2 = 2 what does that mean?
@pgpilot326
I have an idea :D
\[\Large \left.\begin{matrix}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare} \\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare} \end{matrix} \right.\] Looks like a good place to start haha NOW
Let's think columns :) The first column, there are seven squares. At least four of them must be the same colour. Like... obviously haha ;) [Verify that for yourself >:) ] That majority colour... let's just assume it's green, coz you know, green is awesome :)) So, four these must be green..... randomly sprinkling green now... \[\Large \left.\begin{matrix}\color{green}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare} \\\color{green}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{green}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{green}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare} \end{matrix} \right.\] I don't even care what the others are :D
Let's try to do our best NOT to form the rectangle as described :3 In the second column, there are four squares beside the ones in the first column marked green. Crucially, THREE of those four squares have to be red, if you don't want to form that rectangle (prematurely, that is ;) ) So let's randomly sprinkle red. (It doesn't matter which of the seven in the first column are green, and it won't matter which three of the four in the second column corresponding to the four green in the first would be red) \[\Large \left.\begin{matrix}\color{green}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare} \\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{cyan}{\blacksquare} \end{matrix} \right.\]
Can you see it? Once we get to the third column, there are three squares beside the adjacent pairs of squares in green and red. THESE are those three squares. \[\Large \left.\begin{matrix}\color{green}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare} \\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{black}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{black}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{black}{\blacksquare} \end{matrix} \right.\] Two of these have to be the same colour... and if you haven't already seen it, it doesn't matter which two of these share the same colour, or even WHAT colour they are... you WILL form that rectangle that we've so desperately been trying to avoid What a waste of time! HA HA HA Just kidding :)
@PeterPan what you want to say. by making fun here...?
I'm having fun, not making fun ^_^ I think I gave a pretty neat answer :)
Lol peter :)
But in all seriousness, was I correct? :)
sorry no idea for this question... as you have explained in a broad way, so it may be correct
:( Okay
@PeterPan ; You are going in a right direction but I did not get the last part.
Hint provided to me.
its all about possibilitis the thing is it doesnt mintion that how many squars should ne red or green , so i think its possible :P here is someway that make it possible for n x 3 mm this is one way that make it \(\Large \left.\begin{matrix}\color{green}{\blacksquare}\color{red}{\blacksquare}\color{green}{\blacksquare} \\\color{red}{\blacksquare}\color{green}{\blacksquare}\color{red}{\blacksquare}\\\color{green }{\blacksquare}\color{red}{\blacksquare}\color{green}{\blacksquare}\\\color{red}{\blacksquare}\color{green }{\blacksquare}\color{red}{\blacksquare}\\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{green}{\blacksquare}\\\color{red}{\blacksquare}\color{green}{\blacksquare}\color{red}{\blacksquare}\\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{green}{\blacksquare} \end{matrix} \right.\)
What I mean, @imer as soon as we get to the third column, the three squares marked black \[\Large \left.\begin{matrix}\color{green}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare} \\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{black}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{black}{\blacksquare}\\\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\color{cyan}{\blacksquare}\\\color{green}{\blacksquare}\color{red}{\blacksquare}\color{black}{\blacksquare} \end{matrix} \right.\] No matter how you colour these three in red or green, you will inevitably form a rectangle with four corners of the same colour... that's because two of the three will have to be the same colour.
Wait so what does n*2 and n*3 means, does 2&3 number of squares?
@ikram002p : can you please elaborate the question?
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