A 28-g bullet pierces a sand bag that is thick. The initial speed of the bullet is 55 m/s and it emerged from the sandbag at speed 18m/s What is the average magnitude of the friction force that slowed the bullet as it traveled through the bag? 1.3 N 130 N 38 N 13 N
Its s 30 cm thick
use \(\large\sf v^2=u^2-2as\); Take v=18,u=55,s=30 `(convert in m frst)`
find a
I keep getting 4501
multiplied a with mass of bullet ?
When I multiply by mass I find friction is 126
mass is in grams...convert in kg
done ?
Thanks
\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\) \(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)
Join our real-time social learning platform and learn together with your friends!