Question

ALG 2 math help needed!!!
will award medal

Answer 1

i need help plz @Cosmichaotic @quickstudent @waterineyes

Answer 2

I am here only..

Answer 3

I don't know algebra 2. I just starting 1.

Answer 4

So, you have to use some of these here :

\[\large \frac{a^m}{a^n} = a^{m-n}\]
\[\large a^m \cdot a^n = a^{m+n}\]

\[\huge \sqrt[n]{a} = (a)^{\frac{1}{n}}\]

Answer 5

how exactly? do i plug the numbers in?

Answer 6

Do one by one..

Answer 7

alright so i plug what in for n and a though?

Answer 8

First take Joe case:

\[\large \frac{x^{\frac{5}{4}} \cdot x^{\frac{7}{4}}}{x^{\frac{1}{4}}} \implies x^{(\frac{5}{4} +\frac{7}{4} - \frac{1}{4})} \implies x^{\frac{11}{4}} \ne x^4\]

Answer 9

oh alright so joe wouldnt be correct

Answer 10

No..

Answer 11

but wat are you plugging in for n and a in you formula

Answer 12

Now let us do for Deb..

Sorry, are you a girl?? Just asking..

Answer 13

um ya y

Answer 14

I am telling you do one by one, when there will be use of that formula, I will tell you how to use that.. :P Usually, Girls are in a bit hurry to do things hastily..

Answer 15

oh lol ya im in a bit of a time crunch but im sorry if i was being rude!

Answer 16

alright then lets do deb

Answer 17

@waterineyes u there?

Answer 18

Sorry busy helping other person.. So we are on deb..

Can you tell me what will you get when you do this:

\[\large x^3 \cdot x^5 \cdot x^8 = ???\]

Answer 19

x^16

Answer 20

Now we are having use of that Identity.. Now Look here..

Answer 21

n = 4 here and a = \(x^{16}\)

Answer 22

Can you use that??

Answer 23

ya i see

Answer 24

Can you use that or I should explain it??

Answer 25

ya im gonna need it to be explained sorry im kind of dumb

Answer 26

\[\large \sqrt[4]{x^{16}} = (x^{16})^{\frac{1}{4}} \implies x^4\]

Answer 27

Any problem till here, you can surely ask me..

Answer 28

so deb is correct

Answer 29

I don't know who is correct, I just want to know that if you are getting these steps correctly or not??

Answer 30

ya you plug it into
a√n=(a)1n

Answer 31

the equation u gave me in the beginning

Answer 32

is that right

Answer 33

Right.. Good..

Answer 34

Third one is again use of that formula only, try to use that..

Answer 35

i figured it out thanks

Answer 36

That's good.. Welcome dear..