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Mathematics 9 Online
OpenStudy (anonymous):

medals!!! A chemist wants to mix a solution of 75% concentrate with 6 liters of 20% concentrate. How many liters of the 75% concentrate must be used to produce a concentrate of 45%?

OpenStudy (imstuck):

Your equation is made up easily from a table you make with the info they give you. You want to see it?

OpenStudy (anonymous):

yep

OpenStudy (imstuck):

We will call the 75% concentrate solution A, and the 20% concentrate solution B and the end result is Final. OK?

OpenStudy (anonymous):

ok

OpenStudy (imstuck):

You don't know how much solution A you have, only that it is 75% concentrate. You do know that you have 6L of 20%, and that you want, in the end, to to have a solution that is 45% concentrate. So here's your table using that info:

OpenStudy (imstuck):

|dw:1406248769311:dw|

OpenStudy (imstuck):

You need to add the first two solutions to get the final solution, so it looks like this:

OpenStudy (imstuck):

|dw:1406248919930:dw|

OpenStudy (imstuck):

That means you need 5 L of 75% solution.

OpenStudy (anonymous):

5 liters?

OpenStudy (anonymous):

ok thanks :)

OpenStudy (imstuck):

If you have questions about the table, let me know. Ok? Yes, it's 5L of 75% concentrate.

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