medals!!! A chemist wants to mix a solution of 75% concentrate with 6 liters of 20% concentrate. How many liters of the 75% concentrate must be used to produce a concentrate of 45%?
Your equation is made up easily from a table you make with the info they give you. You want to see it?
yep
We will call the 75% concentrate solution A, and the 20% concentrate solution B and the end result is Final. OK?
ok
You don't know how much solution A you have, only that it is 75% concentrate. You do know that you have 6L of 20%, and that you want, in the end, to to have a solution that is 45% concentrate. So here's your table using that info:
|dw:1406248769311:dw|
You need to add the first two solutions to get the final solution, so it looks like this:
|dw:1406248919930:dw|
That means you need 5 L of 75% solution.
5 liters?
ok thanks :)
If you have questions about the table, let me know. Ok? Yes, it's 5L of 75% concentrate.
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