A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

Question

superhelp101 · Answer

@iPwnBunnies

superhelp101 · Answer

@JoannaBlackwelder how do i do this one?

joannablackwelder · Answer

Can you figure out i and m?

superhelp101 · Answer

hmm. can you teach me?

joannablackwelder · Answer

molality is mol solute/kg solvent

superhelp101 · Answer

10.20/355
is this right?

joannablackwelder · Answer

Not quite. that is g solute/g solvent. You need to convert g solute to mol and g solvent to kg

superhelp101 · Answer

how do i convert it?

joannablackwelder · Answer

You need the molar mass of glucose to convert to moles. Can you find that?

superhelp101 · Answer

molar mass of glucose: 180.1559 g/mol

joannablackwelder · Answer

Good. :) Now, |dw:1406243396153:dw|