MASSIVE HELP NEEDED PLEASE
basically i am homeschooled and i am cramming tonight so i can take my math exam tomorrow or i fail
Too many questions at once!
Lets look at the first once
one*
and if i fail i cant go back to regular school in september
okay
So for the first one, you have a line right? To find the slope, take any two points and use the formula of slope I showed you earlier, this one: \[ m = \frac{ y_{2}-y _{1} }{ x _{2}-x _{1} }\]
but there 4 points
Doesn't matter, take any two points, it'll work ;)
ok so (-2,0) and (-5,0) those are correct right?
or is it (0,-2) and (0, -5) ?
You read the graph (x,y)
(-2,0) and (-5,0)
And there is no (0, -5)
** -6
That's (-6, 0)
okay
Lets use (-6,0) and (0,-2)
so i do -2 - (-6)
and 0-0 which is still 0
?
oh wait
would it be 0 - (-6) and 0 - (-2)
0-(-6) is right, but it's -2-(0)
You should really write this out on a piece of paper, or you won't remember.
i am
Ok cool
So the slope will be?
6/ -2 ?
Yeah that = ?
-3
Good job, so, before we go ahead I want to tell you slope intercept looks like y = mx+b form, where m is your slope, b = y - intercept (where the line crosses the y - axis).
wait so how would i write that in slope intercept form?
\[y-y _{1}=m(x-x _{1})\] So now use point - slope form, though there's another way, lets just use this.
Do that first
how :(
No worries, ok we were given points (-6,0) and (0,-2) right?
mhmm
Just plug in y1 and x1 for now and show me what you get
and the slope
this is giving me a head ache ugh but ummm
y1 =0
Mhm I think this website might be better for you, it will show you the steps better, since there is only so much I can do: http://www.mathsisfun.com/equation_of_line.html this will tell you all you need to know.
ive gone over this a million times
i just dont understand it
ok:(
One sec
Yeah, it's fine haha. Alright, so what part are you having trouble at understanding?
how to put something into slope form
Well this is the slope - point form, \[y-y _{1}=m(x-x _{1})\] and what ever our (x1, y1) were we plug it into x1 and y1 in the equation so lets say it was (0, -2) we just do this \[y-(-2)=m(x-0)\] \[y+2=m(x-0)\] and then just distribute \[y+2=mx+0\] solve for y, \[y=mx-2\]
Our slope should be -1/3 actually now that I look at the graph we just mixed up our coordinates :) so your answer should be \[y=-1/3x-2\]
you are honestly a life saver
Hey np, does that make sense?
yes, it does
im writing it all down now
and i just have one more question... Write an equation of a line in slope intercept form that is perpendicular to y = -4x -2 and passes through the point (-16, -11).
no idea how to do that one
Awesome, the thing I figured our slope was wrong, was because look at the graph, the slope is basically telling us this, \[m = \frac{ Rise }{ Run } = \frac{ y_2-y_1 }{ x_2-x_1 }\] So how did I know from the graph? Let me draw it for you. |dw:1406250256262:dw| I used those two points, and y - intercept where the line crosses the y - axis, is the y - intercept (b) in y=mx+b, and looking at the graph slope tells us, y (rise) how many coordinates up and down, and run x (run) left and right, you see how the next point is 3 coordinates to the right of and 1 coordinate down, so looking at the slope formula we would say 1 down, and 3 right, so -1/3.
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