What is the x-intercept of the line given by the equation 2x+3y=12
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OpenStudy (anonymous):
3y=-2y+12
\[y=-\frac{ 2 }{ 3 }x+3\]
OpenStudy (anonymous):
whats the x-intercept?
OpenStudy (anonymous):
1?
OpenStudy (anonymous):
no remember y=mx+b
y=-2/3x+3 x= x-intercept b=y-intercept
OpenStudy (tkhunny):
2x+3y=12
Divide by 12
\(\dfrac{x}{6} + \dfrac{y}{4} = 1\)
Rather staring at you in this, The Intercept Form!
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OpenStudy (anonymous):
Im so lost with this
OpenStudy (anonymous):
when finding the intercepts you need to put it y=mx+b for y=-2/3x+4 what number is with x?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
is the 2 alone?
OpenStudy (anonymous):
-2
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OpenStudy (tkhunny):
When finding the y-intercept, do that.
When finding both intercepts, simultaneously, use the Intercept Form.
Substitute y = 0 for the x-intercept.
Substitute x = 0 for the y-intercept.
OpenStudy (anonymous):
\[y=\frac{ 2 }{ 3 }x+4\]
OpenStudy (anonymous):
im doing it the wrong way my mistake im finding slope tkhunny is right
OpenStudy (anonymous):
2x+3(0)=12
2x=12 whats 12 divided by 2
OpenStudy (anonymous):
6
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OpenStudy (anonymous):
x=6
OpenStudy (tkhunny):
Remember this?
\(\dfrac{x}{6}+\dfrac{y}{4}=1\)
Check out that "6" under the "x".
OpenStudy (anonymous):
looks pretty good
OpenStudy (zzr0ck3r):
this would have been just as easy to leave it in the form it was, let y = 0, and solve for x
OpenStudy (zzr0ck3r):
i.e. solve 2x=12
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OpenStudy (anonymous):
What is the y-intercept of the line given by the equation y=2x-9
OpenStudy (anonymous):
2(0)-9
solve for that
OpenStudy (zzr0ck3r):
for the equation \(y=mx+b\)
\((0,b)\) is the y-intercept
OpenStudy (anonymous):
so y always equals 0?
OpenStudy (zzr0ck3r):
x = 0
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OpenStudy (zzr0ck3r):
\((0,a)\) is the form of the y intercept
\((a,0)\) is the form of the x intercept
OpenStudy (anonymous):
if you're looking for x interecept plug 0 in for y if you're looking for y intercept plug 0 in for x
OpenStudy (zzr0ck3r):
the intercept is not a number though, its the ordered pair