Question

let u = (-3,4)........... write resulting vector in component form and find magnitude....

Answer 1

condition is 3u

Answer 2

-3 is x component of ur given vector u

Answer 3

yes.........i know....

Answer 4

4 is y component of vector u

Answer 5

i just want to know how to find magnitude.......... no clue about that

Answer 6

good

Answer 7

\(||-3i+4j||=\sqrt{(-3)^2+4^2}\)

Answer 8

(-3)^2=?

Answer 9

(-3)^2=3^2

Answer 10

note: this is just the Pythagorean theorem.

Answer 11

k @zzr0ck3r ...... but equals 5......

Answer 12

so that's the magnitude...?

Answer 13

\(||<-3,4>||=\sqrt{3^2+4^2}=\sqrt{25}=5\)
Correct \(\huge \checkmark\)

Answer 14

yes

Answer 15

lol......... dude... the answers says 15....... i am confused as well....

Answer 16

were you given another vector?

Answer 17

the fact that it says resultant vector makes me believe there was more than one vector and you were supposed to do something with it...

Answer 18

surely the magnitude of <-3,4> is not 15

Answer 19

well it had v = (2,4)......... ohh m guessing it has something to do with this

Answer 20

yes

Answer 21

lol....... sorry my bad

Answer 22

post the whole question if you want the whole answer:P

Answer 23

k hang on a sec......

Answer 24

Let u = (-3,4), v = (2,4) and w = (4,-1)........Write each resulting vector in component form and find the magnitude............

question:- 3u

@zzr0ck3r

Answer 25

but either way, \(||<a_0,a_1,a_2,....,a_n>||=\sqrt{a_0^2+a_1^2+a_2^2+.....+a_n^2}\)

Answer 26

k si i knw i got vector correct as (-9, 12)

Answer 27

still not writing the whole question.....

Answer 28

resultant of what?

Answer 29

3u.....

Answer 30

ok then magnitude is then \(\sqrt{9^2+12^2}=\sqrt{81+144}=\sqrt{225}=15\)

Answer 31

and we win \(\huge \checkmark\)

Answer 32

ahh.............. dang it so simple .. so wat did v have to do with this thou??

Answer 33

no idea

Answer 34

are there more questions?

Answer 35

lol...... see that y i only put the value of u up there in first place.............. but yea there are more question..... but i think i am confident enough now to solve them on my own.......................

thx to ur help.........lol.............. Thanks a ton man.......
@zzr0ck3r

Answer 36

npz