For the function \(\normalsize{f(x) = (8-2x)^2}\) ,find \(\normalsize{f-1}\) . Determine whether \(\normalsize{f-1}\) is a function.
Well to find the inverse, here are some steps: To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x)
Ok. Let me see what I can get. If not, I'll need serious help. Cuz this is what one of my answer choice looks like: \[f ^{-1}(x) = \frac{ 8\pm \sqrt{x} }{ 2 }\]
I seem not to understand this problem.
This page helps you determine if a function has an inverse http://www.uiowa.edu/~examserv/mathmatters/tutorial_quiz/geometry/vertandhorizlinetests.html I've highlighted the portion in question (see attached)
Yes, that seems to be correct, to find out if it's a function you can do the horizontal line test.
So, pretty much all I have to do is like find out if it intersects or not?
What about solving though?
you dont need to do that.
if its a function then no one x can point to more than one y
how many answers are there for f(2)?
hint: the \(\pm\) gives it away.
you mean \(f^{-1}(2)\)
yes \(\uparrow\)
I thought that would make it easier, maybe not.:(
that's how I would do it. you have the inverse...use it
@YanaSidlinskiy do you understand? Also, I think you are making it hard on yourself with the normal size stuff `\(\normalsize{f}\)` -> \(\normalsize{f}\) `\(f\)` -> \(f\)
unless you change to something different, and need to go back, there is no point.
Sorry..I was afk. Wow! It's crazy let me think.
Ok. I have 4 multiple choice answers. It's half and half. There's 2 that "is a function" and "is not a function"
so if f^-1 is a function, then you are not allowed to get two answers to f^-1(x) for any x. what is f^-1(2)?
The other one is: \[\pm \sqrt{\frac{ 8+x }{ 2 }}\]
we dont need the options, we know the answer.
better yet, how many answers does f^-1(2) give?
Umm..Like 1 or 2. Right?
\[f ^{-1}(x) = 4 \pm \frac{ \sqrt{x} }{ 2 }~~~ f ^{-1}(2) =?\]
Ok, I was being stupid on this question. Anyways I got the answer:D Thanx for all your help!!!:D Everyone!!!!!!!!!!!! I seriously do appreciate it!
\(\huge\cal\color{Lime}{Thank~you!!!!!!!!}\)
is it a function?
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