Question

Kelly tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," Kelly explains. Using complete sentences, demonstrate to Kelly how the equation is still solvable.

Answer 1

Without knowing what the equation is, it's not easy to say, so I'll use an example.

Suppose you have
\[\frac{1}{x}=1\]
Obviously, \(x\) can't be 0, as that makes the left side undefined. Since \(x\not=0\), you can multiply both sides by \(x\):
\[\frac{x}{x}=x\]
then the left side reduces to get
\[1=x\]

Answer 2

imsooo confused

Answer 3

Not sure how else to explain this, sorry...

Answer 4

can you try it with this equation1/x + 1/(x)² = 2