Find the sum of the first 12 terms of the sequence. 1, -4, -9, -14, . . .
You need to find the difference in each term and use the formula for the nth term. \[n_{th} = a_1+(n-1)d\]
Since you need the sum of the first 12 terms you need to add them all up once you find them.
The sum of that can also be done by a formula.
Most sequences we study are either arithmetic or geometric sequences. Are you familiar with those terms?
\[S_{n} = \frac{ n(a_1+a_n) }{ 2 }\] Where, n = the number of terms you are summing. a1 = the first term. an = the last term.
d= 5 ?
You can use the first formula to find the last term.
Almost your numbers are negative.
And yes, MathStudent
Ok, so you know this is a geometric sequence. To find d, subtract any term from the next one. For example, d = -9 - (-5) = -5
By adding the common difference, you can generate the next several terms. Then add them up to find the sum. Of course, you can also use the formula @Johnbc gave you above.
Thanks!
You're welcome.
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