Question

How many grams of NaOH can be formed when 43.0 grams of Na2O react with 27.0 grams of H2O?

Na2O + H2O yields NaOH

Be sure to balance the equation.

A.13.9 grams
B.18.0 grams
C.27.0 grams
D.55.5 grams

Answer 1

do you know where to start?

Answer 2

First you will have to `balance the equation (as said in the question)`

\(\large \tt Na_2O + H_2O = 2 NaOH\)

Answer 3

Now,
62 grams (1 mole) of \(\sf Na_2O\) reacts with 18 grams (1 mole) of \(\sf H_2O\) to form 80 grams (2 moles) of \(\sf NaOH\)

Answer 4

Now do you know what a `limiting reagent is` ?

Answer 5

43 grams of \(\sf Na_2O\)=0.7 moles
27 grams 0f \(\sf H_2O\)=1.5 moles

Now from the equation we know that 1 mole of water needs 1 mole of \(\sf Na_2O\) to react so 1.5 moles of water will require 1*1.5=1.5 moles of \(\sf Na_2O\) but only 0.7 moles are given. So \(\sf Na_2O\) `will be the limiting reagent.`

Answer 6

Now can u tell me how many moles of NaOH will be formed from 0.7 moles of \(\sf Na_2O\)if one mole of it produces 2 moles of NaOH

Answer 7

80 grams

Answer 8

@jpjones 1.4 moles of NaOH will be formed from 0.7 moles of \(\sf Na_2O\). And 1.4 moles of NaOH = 56 grams