Question

find values f angle B AND B', pic in comments!!

Answer 1

You can use sine rule

Answer 2

\[\large{\cfrac{\sin{\theta}}{12.3} = \cfrac{\sin{B'}}{13}}\]

You are given that \(\large{\theta = 60}\) degrees

Answer 3

Have you read sine rule @nabiladh

Answer 4

yes

Answer 5

Great then use it as I told before :)

Answer 6

\(\color{blue}{\text{Originally Posted by}}\) @vishweshshrimali5
\[\large{\cfrac{\sin{\theta}}{12.3} = \cfrac{\sin{B'}}{13}}\]

You are given that \(\large{\theta = 60}\) degrees
\(\color{blue}{\text{End of Quote}}\)


Using this we can find \(\sin B'\).

Now from sin B' we can calculate B'. --------- ( Ans - 1)

Answer 7

Any doubt ?

Answer 8

would i just plug in 60 for sin theta

Answer 9

Yup sin theta would become sin (60) which is equal to ?

Answer 10

sinB

Answer 11

cross multiply?

Answer 12

Why sin B ?

Answer 13

well it says =

Answer 14

No no \[\large{\sin (60) = 0.866 = \sin{\theta}}\]

Answer 15

Because,
\[\large{\theta = 60}\]

Answer 16

oh ok ok

Answer 17

Using it we can find out the numerical value of sin B'

Answer 18

yeah by cross multipply?

Answer 19

Yes

Answer 20

\[\large{\sin B' = \cfrac{13}{12.3}\sin {\theta}}\]

Answer 21

.915?

Answer 22

Correct

Answer 23

now what do i do witht tht

Answer 24

that*

Answer 25

Now you can use a calculator to find out B'

Answer 26

how on earth will i find that

Answer 27

Sorry I got stuck in other question.

Well you can use a calculator find out arcsin (0.915)

Answer 28

B' = arcsin(0.915)

Answer 29

It is 66.2499 degrees

Answer 30

oh i got 66.21

Answer 31

Yeah...

Sorry I wrote B' in place of B in above comments.

Actually, B = 66.25

Answer 32

yes got confused oops

Answer 33

Sorry again :)

Now the left small triangle is an isosceles triangle

Answer 34

yes yes got it thanks bb

Answer 35

Your welcome :)