*Medal+Fan awarded* Divide Radicals Simplify completely. Answers and Equation - http://imgur.com/G6uCDDU
@esshotwired
@Mashy
@phi
that looks like multiply radicals
It says divide radicals on the practice though
for \[ 2 \sqrt{3} \cdot 4 \sqrt{21} \] which really means multiply all 4 things \[ 2 \cdot \sqrt{3} \cdot 4 \cdot\sqrt{21} \] and when you multiply, you can switch the order (right?) \[ 2 \cdot 4 \cdot \sqrt{3} \cdot \sqrt{21}\]
now you probably can do 2*4 ?
8 lol
ok so far we have \[ 8 \cdot \sqrt{3} \cdot \sqrt{21} \] when we multiply radicals, we can "combine them" using this rule \[ \sqrt{a} \cdot \sqrt{b} = \sqrt{a\cdot b} \] can you use that rule for our problem?
Uhm... No?
the rule says "move" the 3 inside the sqr of 21 (just write 3*21 inside one square root) try it
are you having difficulty write 3*21 inside one square root sign?
Is it D? Just tried the work @phi
Wait scratch that, not D
I have not looked at the answers. We will know the answer after \(\cancel{we} \) you finish.
\[ 8 \cdot \sqrt{3} \cdot \sqrt{21} \\ 8 \cdot \sqrt{3 \cdot21} \]
the next step is factor the 21 can you do that?
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