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Mathematics 16 Online
OpenStudy (zab505):

Need Help!

OpenStudy (zab505):

OpenStudy (zab505):

@mathstudent55

OpenStudy (anonymous):

i think that it is a or c. a is the i am must sure about.

OpenStudy (zab505):

Why?

OpenStudy (anonymous):

what do you mean why?

OpenStudy (zab505):

Its usually 2 answers

OpenStudy (anonymous):

ok so you need to answers

OpenStudy (zab505):

yea

OpenStudy (anonymous):

Now that I look at the question closer I think it is A and D. I can be wrong but I think that the answer is A and D.

OpenStudy (amistre64):

we can test C outright, what are the initial values for f and g?

OpenStudy (zab505):

not sure, there are always two answers

OpenStudy (amistre64):

how can you not be sure what the inital values of f and g are?

OpenStudy (zab505):

0 and 50?

OpenStudy (amistre64):

when x=0, what is f(0)?, what is g(0)?

OpenStudy (amistre64):

another idea: since they are implied to be the same type of function, exponential, then we can determine g's rate by simply dividing off the 50, since exponentials are generally spose to start at 0,1

OpenStudy (amistre64):

the rate of change for g is then, g(1)/50; and the rate of change for f is f(1)/50 ... since they both have the same initial value of 50

OpenStudy (zab505):

What would be the other one?

OpenStudy (amistre64):

what is g(1)?

OpenStudy (amistre64):

what do you mean by 'the other one'?

OpenStudy (zab505):

There are two correct answers

OpenStudy (amistre64):

and instead of just giving them to you straight out, i am trying to foster an environment of study and learning .... guiding you thru a solution process that you can apply to other things.

OpenStudy (zab505):

ah, I do apologize I do want to learn.

OpenStudy (amistre64):

can we rule out D? if so, why?

OpenStudy (zab505):

Don't they both have the same decay?

OpenStudy (amistre64):

decay means they get smaller as x gets bigger. the table for g shows an increase, not a decay ... and f has a rate of 1.4 so it has to get bigger by 140% each time.

OpenStudy (zab505):

ah

OpenStudy (amistre64):

so, the only other option will be to compare the rates. since f(0) = g(0) = 50 is one of the solutions.

OpenStudy (amistre64):

f is stated as 1.4 already g can be determined as g(1)/50

OpenStudy (zab505):

Wait so A?

OpenStudy (amistre64):

youre going to have to compute the rate of change for g.

OpenStudy (amistre64):

if g(0) = 50r^0 = 50 then g(1) = 50r^1 = 75 50r = 75, solve for r

OpenStudy (zab505):

3/2

OpenStudy (amistre64):

good, or 1.5 for easy comparison rate of f is 1.4 rate of g is 1.5 is A correct or incorrect?

OpenStudy (zab505):

incorrect

OpenStudy (amistre64):

then lets go with B :)

OpenStudy (zab505):

Wow thank you so much!

OpenStudy (amistre64):

good luck :) ad thinks for the participation, it really helps

OpenStudy (zab505):

thank you!

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