Question

HELPP! Will Fan and Medal!.Find the 7th partial sum of summation of 6 open parentheses 3 close parentheses to the I minus 1 power from 1 to infinity.

Answer 1

@PFEH.1999

Answer 2

u mean this?
\(\Large \sum_{i=1}^{\infty} 6 (3)^{i-1}\)

Answer 3

Yess! Can you help? ;c

Answer 4

i got 4374?

Answer 5

let me check...

Answer 6

2,184

6,558

27,993

167,961
These are the answer choices D;

Answer 7

sry it seems some mistake has been made...let me check again.

Answer 8

Okay :c

Answer 9

sry ;) maybe have forgot all about sum :P

you have to find the sum of i=1 up to i=7...so substitute i=1 and find it then substitute i=2 then find it and do this up to i=7 and then find sum of all of them:
4374 + 1458 + 486 + 162 + 54 + 18 + 6 = 6,558

Answer 10

the second one ;)

Answer 11

Aweh c: Thank you! Can you help me with a few more?

Answer 12

sure ;)

Answer 13

Identify whether the series summation of 16 open parentheses 5 close parentheses to the I minus 1 power from 1 to infinity is a convergent or divergent geometric series and find the sum, if possible.

This is a convergent geometric series. The sum cannot be found.

This is a divergent geometric series. The sum cannot be found.

This is a convergent geometric series. The sum is –4.

This is a divergent geometric series. The sum is –4.

Answer 14

Nevermind! i got it c: Thanks @PFEH.1999 c:

Answer 15

oh sry @MarrBear ,