Question

MEDAL AND FAN!

QUESTION BELOW

Answer 1

26 = -16t^2 +4t+26

Answer 2

simplify that then best you can.

Answer 3

Let h = 26, and solve for t.

Answer 4

So you then would have 0 = -16t^2 +4t, right?

Answer 5

in choices it says sec, so I thought it is trigonometric sec (x) :)

Answer 6

Just substitute the given answers and check if h will be 26.. that's the easiest way!!

Answer 7

THANKS GUYS! idk who to medal though xD

Answer 8

16t^2 - 4t =0
t(16t - 4) = 0
t= 1/4

Answer 9

let me show you something here very quick.

\(\normalsize\color{blue}{ \rm {h} = -16t^2+4t+26 }\)
\(\normalsize\color{blue}{ \rm {h} = -16t^2+4t-4+30 }\)
\(\normalsize\color{blue}{ \rm {h} = -16(t^2-\frac{1}{4}t+\frac{1}{4})+30 }\)
\(\normalsize\color{blue}{ \rm {h} = -16(t-\frac{1}{2})^2+30 }\)

Answer 10

\(\normalsize\color{blue}{ \rm {y} =a(x-h)^2+k~~~~~~~\color{black}{\rm{center:~~(x,h)}} }\)

Answer 11

Sorry for the late reply, but your function is a vertical, ∩-shaped parabola.