Question

Find the restrictions...

Answer 1

I think they are all real numbers. But not sure...:/

Answer 2

@ganeshie8

Answer 3

@paki

Answer 4

what is your question...?

Answer 5

To solve, but I already did. Then to list the restrictions, which I think is all real numbers

Answer 6

@SolomonZelman please help here...

Answer 7

@TheRealRyGuy help here...

Answer 8

whats the problem

Answer 9

to solve for any restrictions here:

Answer 10

\(\Large\cal\color{red}{ok~let~me~help}\)

Answer 11

the attachment isn't working for me, but a restriction is a value of a variable with which you will have a square root equal to a negative number, or a value of a variable that makes any denominator be equal to 0.

Answer 12

\(\Large\frak\color{red}{Doesn't~work~for~me~either}\)

Answer 13

oh it was the same problem that @SolomonZelman solved before. But I will rewrite it...

Answer 14

I remember it

Answer 15

\(\Large\cal\color{pink}{good ~luck}\)

Answer 16

\(\huge\color{blue}{ \frac{4t^2-1}{15t+10}\div \frac{4t^2-4t+1}{5t^2+3t+2} }\)

Answer 17

Am I right ?

Answer 18

yes ;)

Answer 19

wait no....

Answer 20

\(\huge\color{blue}{ \frac{4t^2-1}{15t+10}\div \frac{4t^2-4t+1}{5t^2+3t+2}= }\)

\(\huge\color{blue}{ \frac{4t^2-1}{15t+10}\times \frac{5t^2+3t+2}{4t^2-4t+1}= }\)

\(\huge\color{blue}{ \frac{(4t^2-1)(5t^2+3t+2)}{(15t+10)(4t^2-4t+1)}. }\)

Answer 21

\[(4t^2-1)/(15t+10) \div (4t^2-4t+1)/(3t^2+5t+2)\]

Answer 22

(15t+10)(4t²-4t+1) = 0 to solve for the restrictions.

Answer 23

oh okay so it's always going to use the denominator..

Answer 24

the denominator of that problem is going to be 5(2t-1)=0. So to find the restrictions we need to set 5=0 and 2t-1=0 to get t=1/2. So 1/2 is our restriction?

Answer 25

\(\large\color{blue}{ (15t+10)(4t^2-4t+1)≠0}\)

\(\large\color{blue}{ 5(3t+2)(4t^2-4t+1)≠0}\)

\(\large\color{blue}{ 5(3t+2)(2t-1)^2≠0}\)

\(\large\color{blue}{ (3t+2)(2t-1)^2≠0}\)
─────────────────────────

\(\large\color{blue}{ (3t+2)≠0~~~~~~~~~~\rm{or}~~~~~~~~~~(2t-1)^2≠0}\)

\(\large\color{blue}{ t≠-3/2~~~~~~~~~~~~~~~~~~~~~~~~~~~~2t-1≠0}\)

\(\large\color{blue}{ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~t≠1/2}\)

Answer 26

Clear ?

Answer 27

\(\Large\cal\color{green}{Great~Job~Soloman}\)

Answer 28

tnx, real guy.

Answer 29

sorry I think we got the right problem here...

Answer 30

somoen gmme medal pls all i need is one more

Answer 31

\[(4t^2−1)/(15t+10)÷(4t^2−4t+1)/(3t^2+5t+2)\]

Answer 32

YAY