A building lot in a city is shaped as a 30° -60° -90° triangle. The side opposite the 30° angle measures 41 feet. a. Find the length of the side of the lot opposite the 60° angle. b. Find the length of the hypotenuse of the triangular lot. c. Find the sine, cosine, and tangent of the 30° angle in the lot. Write your answers as decimals rounded to four decimal places
http://www.gradeamathhelp.com/image-files/30-60-90-triangle.jpg <--- use the 30-60-90 rule that would cover first two parts a and b as far as part c well, recall your SOH CAH TOA -> http://media-cache-ak0.pinimg.com/736x/6f/8c/52/6f8c52f52f9aced5c80d3dc4410e3daf.jpg
so what are the answers for the following that is listed in the question
I do no understand the answer to the question. May you please explain?
According to @jdoe0001 you may get what you need its on you now .. SOH?= sin 30 = 41feet/Hypotenuse ?.. equals to 82 ? not sure of this -_- ..And for the tree? sin 30 = 0.5 ? cosin 30 = 0 .866 tan 30 = 0.577 ? and at the a. amm i think it is the adjacent angle? so you'll use tan 60 = opposite/adjacent which is the opposite is 41 right?. then the adjacent is 23.67 ? :3 really not sure of that -_- ..
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