Question

in a reaction a+b<===> c+d, the initial concentration of a and b were 0.9 m0l/dm3 each. at equilibrium the concentration of d was found to be 0.6 m0l/dm3. what is the value of equilibrium for the reaction?
a.8 b.4 c. 9 d.3

Answer 1

@Abmon98 ya know how to solve it ?

Answer 2

Kc=[Products]^n/[Reactants]^n
in a reaction a+b<===> c+d
Initial concentration 0.9, 0.9 - -
Change in concentration -0.6, -0.6, +0.6, +0.6
at equilibrium 0.3, 0.3, 0.6
i think because the coefficient of all reactants and products so c must also have a concentration at equilibrium of 0.6
[0.6]^2/[0.3]^2

Answer 3

So what should be the correct answer :/

Answer 4

its 4 right ?

Answer 5

yes 4

Answer 6

Thanks a lot ^_^

Answer 7

your most welcome :)