Find the coordinates of the intersection of the diagonals of parallelogram WXYZ with the following vertices: W(0,0),X(2,4),Y(12,6),Z(10,2)
hmm have you drawn them yet? can you tell where it might be?
I've drawn the parallelogram. I'm just unsure what its asking. Is there an equation to find the coordinates of the intersection of the diagonals of a parallelogram?
well..... anyhow... the parallelogram is more or less like |dw:1406331158559:dw| so... now.. can you draw on that graph the diagonals?
I'm confused about what a diagonal is.
a line that goes from one corner to the OPPOSITE corner
|dw:1406331052772:dw|
|dw:1406331709399:dw|
so that means if you want to know where the diagonals are intersecting, and thus cutting each other in half that will be the "midpoint" of the line WY or the "midpoint" of the line XZ thus \(\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ X&({\color{red}{ 2}}\quad ,&{\color{blue}{ 4}})\quad Z&({\color{red}{ 10}}\quad ,&{\color{blue}{ 2}})\\ W&({\color{red}{ 0}}\quad ,&{\color{blue}{ 0}})\quad Y&({\color{red}{ 12}}\quad ,&{\color{blue}{ 6}}) \end{array}\qquad \left(\cfrac{{\color{red}{ x_2}} + {\color{red}{ x_1}}}{2}\quad ,\quad \cfrac{{\color{blue}{ y_2}} + {\color{blue}{ y_1}}}{2} \right)\)
so the answer would be (6,3)?
yeap
Thank you
check your graph....it'd be at 6,3 :) yw
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