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According to the reaction shown, how many moles of oxygen gas are necessary to produce 24.0 g of Li2O? 4Li + O2 --> 2Li2O I did 24/29.88 = .803 since it is a 1:2 ratio I divided by 2 and got .402mol right?
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yes that's right :).
yassssss finally getting a hold of this haha thanks @Abmon98
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