The sides of a quadrilateral are 3,4,5 and 6. Find the length of the shortest side of a similar quadrilateral whose area is 9 times as great. 9 13.5 27
@ganeshie8
@driftracer305
@satellite73
@Zarkon
if area is \(\large k\) times greater, then the side will be \(\large \sqrt{k}\) times greater
So the shortest side that we know is 3 so 3k
So 27
area goes with the square if the area is 9 times as great then each side is 3 times as large
Oh ok thanks for taking the time to help me
a simple example would be a square of side say 5 the area would be 25 then \(9\times 25= 225\) and if a square had an area 225 then the side would be length \(3\times 5=15\)
hope it is clear yw
Yeah that helped, do you mind helping me with one more
i kind of suck at geometry but i could try
if i can't help i will just say so
Ok thanks. A circle has a radius of 6 in. The inscribed equilateral triangle will have an area of?
i think it is \[\frac{\sqrt3}{4}r^2\]right?
|dw:1406341483984:dw|
unless you need a proof that should work
Hmmidk for sure I'll try that out
wait hold the phone that is wrong it is three times that
I just wants the answer that is two digits times the square root of one for the answer
It*
damn typo \[\frac{\sqrt3}{4}\times 6^2\times 3\]
Ahh ok thanks, too many formula to memorize and I'm having to teach this to myself
better know as \(27\sqrt3\)
i could explain it but not without trig
Ok thanks for the help, I appreciate it
yw
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