HELP!
here i come to the rescue!
1+2+5 AND THE EQUAL SIGN HAVE 3 LINES (MOD 6)
\[1+2+3\equiv (6)\]
\[1+2+5\equiv ? \mod 6\]
yes, just like geneshie8
short answer is : add the numbers on left hand side, and subtract 6's until you get a number less than 6
2?
Yep ! and 2 is a remainder when you divide the left hand side stuff by 6
so modulo is just like subtraction the number?
yes, but nobody thinks of it like that when they work it :)
here is the actual definition of modulo : \(\large a \equiv b \mod n\) means \(\large (a-b)\) is divisible by \(\large n\)
but for the problems you have been doing, you may think of it as sequence of subtractions... which is indeed a division, and the number you endup with is a `remainder`
awesome
\[a \ge-12\]
|dw:1406342491864:dw|
\[\large 4 - x \equiv 5 \mod 8\] you can subtract 5 both sides, the remainder wont change : \[\large 4-5 - x \equiv 0 \mod 8\] \[\large -1 - x \equiv 0 \mod 8\]
Next, notice that left hand side is divisible by 8 when x = 7
where is x=7?
|dw:1406343084755:dw|
Yep ! it can be 7
ohhh so 7 would be the answer
yes, 7 is a good answer in mod 8
Thank you very much
np :)
do you mind if I send you a message if I have a question in the future?
sure you can :) you may ask a question directly in openstudy also... so many ppl are good with number theory here !
I definitely will. thank you again.
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