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Mathematics 6 Online
OpenStudy (anonymous):

HELP!

OpenStudy (anonymous):

here i come to the rescue!

OpenStudy (anonymous):

1+2+5 AND THE EQUAL SIGN HAVE 3 LINES (MOD 6)

OpenStudy (anonymous):

\[1+2+3\equiv (6)\]

ganeshie8 (ganeshie8):

\[1+2+5\equiv ? \mod 6\]

OpenStudy (anonymous):

yes, just like geneshie8

ganeshie8 (ganeshie8):

short answer is : add the numbers on left hand side, and subtract 6's until you get a number less than 6

OpenStudy (anonymous):

2?

ganeshie8 (ganeshie8):

Yep ! and 2 is a remainder when you divide the left hand side stuff by 6

OpenStudy (anonymous):

so modulo is just like subtraction the number?

ganeshie8 (ganeshie8):

yes, but nobody thinks of it like that when they work it :)

ganeshie8 (ganeshie8):

here is the actual definition of modulo : \(\large a \equiv b \mod n\) means \(\large (a-b)\) is divisible by \(\large n\)

ganeshie8 (ganeshie8):

but for the problems you have been doing, you may think of it as sequence of subtractions... which is indeed a division, and the number you endup with is a `remainder`

OpenStudy (anonymous):

awesome

OpenStudy (anonymous):

\[a \ge-12\]

OpenStudy (anonymous):

|dw:1406342491864:dw|

ganeshie8 (ganeshie8):

\[\large 4 - x \equiv 5 \mod 8\] you can subtract 5 both sides, the remainder wont change : \[\large 4-5 - x \equiv 0 \mod 8\] \[\large -1 - x \equiv 0 \mod 8\]

ganeshie8 (ganeshie8):

Next, notice that left hand side is divisible by 8 when x = 7

OpenStudy (anonymous):

where is x=7?

ganeshie8 (ganeshie8):

|dw:1406343084755:dw|

ganeshie8 (ganeshie8):

Yep ! it can be 7

OpenStudy (anonymous):

ohhh so 7 would be the answer

ganeshie8 (ganeshie8):

yes, 7 is a good answer in mod 8

OpenStudy (anonymous):

Thank you very much

ganeshie8 (ganeshie8):

np :)

OpenStudy (anonymous):

do you mind if I send you a message if I have a question in the future?

ganeshie8 (ganeshie8):

sure you can :) you may ask a question directly in openstudy also... so many ppl are good with number theory here !

OpenStudy (anonymous):

I definitely will. thank you again.

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