Question

question!

Answer 1

@aum help please!

Answer 2

The link shows a blank page.

Answer 3

hold on a sec

Answer 4

Find the length of AB.
Find the length of A'B'
The ratio of the lengths will give the scale factor.

Answer 5

How would i find the length?

Answer 6

Subtract them?

Answer 7

Use the distance formula. Distance between \((x_1,y_1)\) and \((x_2,y_2)\) is:

\(\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)

Answer 8

4?

Answer 9

A (9,4), B (5, -4)
Length of AB = \(\sqrt{(9-5)^2 + (4 - (-4))^2} = \sqrt{4^2+8^2} = \sqrt{16+64} \\ =
\sqrt{80} = \sqrt{16 * 5} = 4\sqrt{5} \).

Do the same with A'B'

Answer 10

5 sqrt 2? @aum

Answer 11

A' (6,3), B' (3, -3)
Length of A'B' = \(\sqrt{(6-3)^2 + (3 - (-3))^2} = \sqrt{3^2+6^2} = \sqrt{9+36} \\ =
\sqrt{45} = \sqrt{9 * 5} = 3\sqrt{5}\).

Scale factor = Length of the image A'B' / Length of the original AB =
\(\Large \frac{3\sqrt{5}}{4\sqrt{5}} = \frac 34\)

Answer 12

Thank you!

Answer 13

You are welcome.