Question

For the given function, find the vertical and horizontal asymptote(s) (if there are any).

Answer 1

\[f(x)= \frac{ 2x ^{2}+1 }{ x ^{2-4}}\]

Answer 2

@Cosmichaotic

Answer 3

Get zero's set
by making the x^2 - 4 = 0
x= +-2 that is the vertical as it can't reach it.
for the horizontal.Put x goes to infinity you will get y = 2
you can make sure by drawing it there
http://graphsketch.com/

Answer 4

Thank you c:

Answer 5

x=2
x= -2
y= 2

Answer 6

right?

Answer 7

you are welcome
you know differentiation right?

Answer 8

right?
Do you know how to get it yourself??

Answer 9

Yep, I figured out the rules

Answer 10

Thank you v much

Answer 11

Your text didn't give you rules?