Question

y=3x+3
2y= 2/3x +12 how to solve to systems of equation?

Answer 1

Isolate one of the variables of one of the equations (doesn't matter what variable or equation, but some ways will be easier than others)
Your y is already isolated, now can substitute it into the other equation. Wherever there is a y in the second equation, put in what is on the right of the first equation
2(3x+3)=2/3x +12
Then solve for x
Once you get that x, plug it back into one of the equations (doesn't matter which, again some ways will be easier than others) and solve for y then

Answer 2

6x+6 = 2/3x +12. I am confuse what to do next tho?

Answer 3

Do I take the 6 out or 6x?

Answer 4

first put all the x on one side

Answer 5

and everything else on the other side

Answer 6

Do I subract 2/3 to 6x

Answer 7

okay do that to both sides of the equation what happens?

Answer 8

Wait do I need to find common bottom for this one?

Answer 9

yes

Answer 10

I got 6/3.

Answer 11

\[6x+6\color \red {-6} = \frac{2x}{3} +12\color \red {-6} \\
6x = \frac{2x}{3} +6\\
6x-\color \red{\frac{2x}{3}} = \frac{2x}{3} +6-\color \red{\frac{2x}{3}} \\
5x+\frac{x}{3}=6\\
16x/3=6\\
16x=18 \\
x=18/16\]