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Mathematics 16 Online
OpenStudy (precal):

For what values of x does the graph of g have a point of inflection

OpenStudy (precal):

OpenStudy (owlcoffee):

The points of inflection are the points where the 2nd derivative is 0. or in other words, where the function changes concavity.

OpenStudy (anonymous):

Take the derivative of g(x) you get f(x) so g'(x) = f(x) and g '' (x) = f'(x). So if you take 1st derivative of f(x) and find where it's 0. That's the point of inflection on the 2nd derivative of g(x). Seems to me that it's the max at 2 and min at 5.

OpenStudy (precal):

ok but don't I have to evaluate that integral g ' (x)=f (x) g " (x)= f ' (x)

OpenStudy (phi):

yes, you want g'' = 0 which means f' = 0 which occurs at x=2 and x=5

OpenStudy (precal):

thanks everyone

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