Can you factorise \(\sf \large \frac{4AB}{(A+B)(A+B)}\) to \(\large\sf\frac{4B}{A}\)
what?
one min !
factorization or factoring is the decomposition of an object into a product of other objects
\(\sf \large \frac{4AB}{(A+B)(A+B)}\) to \(\large\sf\frac{4B}{A}\)
if its for explanding brackets \[a(b + c) \], the expanded version is \[ab + ac\]
Uhm It is not correct: \[\large{\cfrac{4AB}{(A+B)^2} \ne \cfrac{4B}{A}}\]
yep..that's what i was thinkin !
for that denominator must equal a^2 ,, , so no
may be i should post the original question. But it's physics
Find the ratio x:y if x= \(\sf \large \frac{CAB}{d^2}\) y= \(\sf \large \frac{C\times (A+B)/2\times (A+B)/2}{d^2}\)
\[\large{x:y = \cfrac{4AB}{(A+B)^2}}\]
Doesn't appear to be a Physics question @Abhisar O.o :)
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