Question

help me find the "t".. im sorry im quite confuse.

d = vt + gt^2/2

Answer 1

i'm kinda stuck at this part.

2d/2vgt = t

Answer 2

Does it look like this?:
\[d=\frac{ vt+g t ^{2} }{ 2 }\]

Answer 3

Does this problem state that initial velocity is 0?

Answer 4

nope...

\[d = vt + \frac{ g t ^{2} }{ 2 }\]

the velocity is 12.4 m/s... and this problem is more on projectile motion

Answer 5

Can you copy and paste the whole problem?

Answer 6

it will have 2 solutions for t second degree equation.

Answer 7

1.) A dart player throws a dart horizontally at a speed of 12m/s. The dart hits the board 0.32 m below the height from which it was thrown

-a.) How long did the dart travel?

-b.) How far away is the player from the board?


so far i wrote down the given: Vox = 12.4m/s ; dy = -0.32m
i'm not even sure with the given

Answer 8

put it in the form \[a x ^{2}+b x+c = 0\]
and use the formula
\[\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 9

i already converted some. all i need is just to find the y

Answer 10

quadratic formula?

Answer 11

Hey man v0 is zero.

Answer 12

umm... the vy is 0... since it says horizontal... it means its traveling on the x axis...