Question

If it requires 7.0J of work to stretch a particular spring by 1.8cm from its equilibrium length, how much more work will be required to stretch it an additional 4.2cm ?

Answer 1

Hello @zfower3317 !
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Answer 2

Have you tried it yourself ?

Answer 3

Work done on the spring gets stored as its potential energy. Potential energy of a spring is given by \(\large\sf \frac{1}{2}kx^2\).

-->\(\large\sf \frac{1}{2}k(1.8\times10^{-2})^2=7\). Now find the value of k

Answer 4

Substitute this value in the equation \(\large\sf \frac{1}{2}k(4.2\times10^{-2})^2\). This will give you the work required in displacing the spring by 4.2 cm. Subtract 7 from it and it will give you the answer.

Answer 5

Got it ?

Answer 6

yeah i think i get now thanks

Answer 7

\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\)
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