Question

can anyone help me? simplify and leave in radical form

Answer 1

I'm not sure how to explain how to solve this but here are the steps:

Since x^6*x^2= x^8 (Due to fractional rules), that means that the answer is \[\sqrt[8]{x^8}\]

If you are putting it in rational form it is basically x^8/8, or just x.

Hope this helped!

Answer 2

\(\Large {
\bf a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \sqrt[{\color{red} m}]{a^{\color{blue} n}}
\\ \quad \\ \quad \\

\sqrt[{\color{red}{ 8}}]{x^2y^6}\implies (x^2y^6)^{\frac{1}{{\color{red}{ 8}}}}\implies x^{\frac{\cancel{ 2 }}{\cancel{ 8 }}}y^{\frac{\cancel{ 6 }}{\cancel{ 8 }}}\implies ?
}\)

Answer 3

hmmm I meant to put anyhow \(\Large \bf a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad

\sqrt[{\color{red} m}]{a^{\color{blue} n}}=a^{\frac{{\color{blue} n}}{{\color{red} m}}}\)

Answer 4

so... how would those 2 fractions simplify to ?

Answer 5

\[(x ^{2}y ^{6})^{1/8}\]Use the rule for exponents.

Answer 6

\[\sqrt[8]{x^{2}y^{6}}\]
since they are all divisible 2 then:
\[\sqrt[2(4)]{(xy^{3}){2}}\]
(cancel out 2)
its simplified form is:
\[\sqrt[4]{xy ^{3}}\]