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Given the function f(x) = 4(x+3) − 5, solve for the inverse function when x = 3. −21 −16 −10 −1
\(\bf f(x)={\color{brown}{ y}} = 4({\color{blue}{ x}}+3) - 5\qquad inverse\to {\color{blue}{ x}}= 4({\color{brown}{ y}}+3) - 5\leftarrow f^{-1}(x)\) so, to get the inverse "relation", we simply swap about the variables, and then just solve for "y" then plug in 3 in it, that is, set x =3
i tried already and got 19..
@jdoe0001
hmmm \(\bf f(x)={\color{brown}{ y}} = 4({\color{blue}{ x}}+3) - 5\qquad inverse\to {\color{blue}{ x}}= 4({\color{brown}{ y}}+3) - 5\leftarrow f^{-1}(x) \\ \quad \\ x+5=4(y+3)\implies \cfrac{x+5}{4}=y+3\implies \cfrac{x+5}{4}-3=y\leftarrow f^{-1}(x) \\ \quad \\ f^{-1}({\color{purple}{ 3}})=\cfrac{{\color{purple}{ 3}}+5}{4}-3\implies ?\)
-1 ?
yeap
ok thanks
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