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If delta H= -70.0 kJ and delta S = -0.400 kJ the reaction is spontaneous below a certain temperature. Calculate the temperature in Kelvins.
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\(\Delta G=\Delta H-T\Delta S\) spontaneity implies that \(\Delta G<0\) set: \(\Delta G=\Delta H-T\Delta S=0\) plug your values in and solve for T
So it would be 280 K?
Thats not what i got, double-check your algebra
I got 28?
\(-70.0-(T*-0.4)=0\) \(-70.0+T*0.4=0\) \(0.4T=70\) \(T=\dfrac{70}{0.4}=175~K\)
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how did T become positive?
I see!!
The two negative signs cancelled out: -(-0.4)=0.4
Thank you so much!!!
no problem!
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