Question

When a strip of zinc is placed in a solution of silver nitrate, Zn replaces Ag to form zinc nitrate, and metallic silver is formed. How many moles of silver will be generated if 1.30 moles of zinc is placed into the silver nitrate solution?
2AgNOÀ + Zn d 2Ag + Zn(NOÀ)¿

Answer 1

Make a ratio of the moles and the stoichiometric coefficients

\(\sf \dfrac{moles~of~Zn}{1}=\dfrac{moles~of~Ag}{2}\)

plug in moles of Zn and solve for moles of Ag

Answer 2

2 AgNO3 + Zn → Zn(NO3)2 + 2 Ag
(1.30 mol Zn) x (2 mol Ag / 1 mol Zn) = 2.60 mol Ag