reward 20 medals find g(x) number 3 http://assets.openstudy.com/updates/attachments/53d4352ee4b081ba963ba333-jenniferjuice-1406416967388-thing1and2.png http://assets.openstudy.com/updates/attachments/53d4352ee4b081ba963ba333-jenniferjuice-1406416697002-yah.png the question is #3 : http://assets.openstudy.com/updates/attachments/53d43236e4b081ba963ba209-jenniferjuice-1406415438454-onemore.png i have to find g(x)
@rock_mit182 this is the work sheet
most quadratics don't come neatly squared like this. For your average everyday quadratic, you first have to use the technique of "completing the square" to rearrange the quadratic into the neat "(squared part) equals (a number)"
how?
make g(x) --> 0
cause we need to find the roots of the function or in other words its solution
\[g(x) =0\] \[x ^{2} +6x +1 = 0 \]
g(x)= x^2 + 6x + 1 ?
Move the loose number over to the other side.
in this case is 1
\[x ^{2}+6x = -1\]
wait so..? what do i do now?
Divide through by whatever is multiplied on the squared term.
in this case 1, that means no change
Now ,Take half of the coefficient (don't forget the sign!) of the x-term, and square it. Add this square to both sides of the equation
ready, how the equation looks like now ?
hold up i lost my pencil
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