Question

What value is a discontinuity of x squared plus 8 x plus 4, all over x squared minus x minus 6?

x = -1

x = -4

x = -3

x = -2

Answer 1

This is \(\dfrac{x^2+8x+4}{x^2-x-6}\)

Answer 2

yes

Answer 3

and is discontinuous when the denominator is 0

Answer 4

the discontinuity value is when denominator is zero, so set denominator equal to 0 and solve.
\(x^2-x-6=0\)

Answer 5

x=-3???

Answer 6

none. do you know how to solve it? try to factor \(x^2-x-6\)

Answer 7

how do you do that