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Mathematics 17 Online
OpenStudy (anonymous):

Help again..

OpenStudy (anonymous):

OpenStudy (anonymous):

I believe the answer would be 45. Because you would divide 360/4 and then divide that by 2!!

OpenStudy (anonymous):

@Ashleyisakitty

OpenStudy (anonymous):

@YanaSidlinskiy

OpenStudy (anonymous):

@xapproachesinfinity

OpenStudy (xapproachesinfinity):

should be 30 degrees

OpenStudy (anonymous):

okay how..

OpenStudy (xapproachesinfinity):

i'm sorry 45

OpenStudy (anonymous):

okay phew I was scared there for a second.

OpenStudy (xapproachesinfinity):

I'm drunk lol, the diameters are perpendicular to each other then the angle is 90

OpenStudy (yanasidlinskiy):

After you know how much degrees a quadrilateral is, divided by how many spaces there is.

OpenStudy (anonymous):

okay..im confused..

OpenStudy (xapproachesinfinity):

exactly!

OpenStudy (xapproachesinfinity):

For a moment I was thinking about something else lol

OpenStudy (yanasidlinskiy):

How much degrees is there in a quadrilateral? Hahahha.

OpenStudy (xapproachesinfinity):

hahaha sounds a good question

OpenStudy (anonymous):

360

OpenStudy (xapproachesinfinity):

let me make a guess lol, could be 360?

OpenStudy (anonymous):

so...was my answer right or wrong..

OpenStudy (xapproachesinfinity):

Correct!

OpenStudy (yanasidlinskiy):

Lets see:) And how many angles is there?

OpenStudy (anonymous):

4

OpenStudy (yanasidlinskiy):

360/4=??

OpenStudy (anonymous):

90

OpenStudy (xapproachesinfinity):

well a quadrilateral could have angles that are greater or less than 90 but the total is still 360 degrees

OpenStudy (yanasidlinskiy):

So now..you would get half of 90 and its 45:) So..You're correct!!!!!!!!!!!!!! Great job!!:)

OpenStudy (anonymous):

thanks since you are so good with this do you find helping me with other questions..cause im so lost

OpenStudy (anonymous):

@xapproachesinfinity

OpenStudy (xapproachesinfinity):

Yah go a ahead, I thought you were asking Yana lol

OpenStudy (anonymous):

no haha I was asking you

OpenStudy (anonymous):

OpenStudy (xapproachesinfinity):

ok so try to find out what a is using pythagorean theorem, that little triangle has equal sides

OpenStudy (anonymous):

How could you do that if you are only given the hypotenuse??

OpenStudy (xapproachesinfinity):

a^2 + a^2=r^2 how is this?

OpenStudy (xapproachesinfinity):

does is make sense

OpenStudy (xapproachesinfinity):

it

OpenStudy (anonymous):

um not really.. I no that r would equal 6 when squared

OpenStudy (anonymous):

know*

OpenStudy (xapproachesinfinity):

r^2=9.2=18 right but don't forget the LHS

OpenStudy (anonymous):

oh god...so what is the answer?? What does LHS stand for?? Sorry If I am be annoying...

OpenStudy (xapproachesinfinity):

no problem my friend we are here to learn, I you don't know something stop me and ask.

OpenStudy (xapproachesinfinity):

so LHS stands for left hand side

OpenStudy (anonymous):

a would be 9 then right? Oh okay thanks.

OpenStudy (xapproachesinfinity):

No, you a^2=9 not a

OpenStudy (xapproachesinfinity):

you are almost there continue

OpenStudy (xapproachesinfinity):

I mean a^2=9 not a

OpenStudy (anonymous):

okay so knowing that a^2=9 what do you do next... do you plug it back into the a^2+a^2=9 equation??

OpenStudy (xapproachesinfinity):

No, now use square root of both sides you should get a=sqrt{9}

OpenStudy (xapproachesinfinity):

what is square root of 9

OpenStudy (anonymous):

3

OpenStudy (xapproachesinfinity):

good! so... a= what

OpenStudy (anonymous):

3

OpenStudy (xapproachesinfinity):

Great job! so we found a=3 so what do we do next

OpenStudy (anonymous):

you would use the equation 1/2(r)(p)=Area.. I think

OpenStudy (xapproachesinfinity):

Now that we found a, we still need something because a is just half the length of that quadriletral

OpenStudy (anonymous):

you need the length of a side

OpenStudy (xapproachesinfinity):

Not that equation, that's for only triangles

OpenStudy (xapproachesinfinity):

yes!

OpenStudy (xapproachesinfinity):

we found half of that length what do we do

OpenStudy (xapproachesinfinity):

now

OpenStudy (anonymous):

we would add six again and the length would equal 12

OpenStudy (xapproachesinfinity):

no we add 3 we got 6, so the length is 6

OpenStudy (xapproachesinfinity):

one more step and done

OpenStudy (anonymous):

we would just multiply 6 by 6|dw:1406425872248:dw| and the area would be 36

OpenStudy (xapproachesinfinity):

yay! great job

OpenStudy (xapproachesinfinity):

area= b^2, b is the length, you have done a great job

OpenStudy (anonymous):

Oh good thanks! I have one more question..that I need help with if you don't mind helping that would be great but let me open it in a new post cause I want to give you two medals!

OpenStudy (xapproachesinfinity):

I'm sorry but im running out of time, I have to go for prayer and come back. really sorry . I'm proud of you. you're learning fast

OpenStudy (xapproachesinfinity):

I'm doing Ramadan lol, So i need to go pray in the mosque ^^

OpenStudy (anonymous):

aww okay thanks! have fun at prayer.

OpenStudy (xapproachesinfinity):

you are welcome, thanks^^

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