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OpenStudy (anonymous):
OpenStudy (anonymous):
I believe the answer would be 45.
Because you would divide 360/4 and then divide that by 2!!
OpenStudy (anonymous):
@Ashleyisakitty
OpenStudy (anonymous):
@YanaSidlinskiy
OpenStudy (anonymous):
@xapproachesinfinity
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OpenStudy (xapproachesinfinity):
should be 30 degrees
OpenStudy (anonymous):
okay how..
OpenStudy (xapproachesinfinity):
i'm sorry 45
OpenStudy (anonymous):
okay phew I was scared there for a second.
OpenStudy (xapproachesinfinity):
I'm drunk lol, the diameters are perpendicular to each other then the angle is 90
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OpenStudy (yanasidlinskiy):
After you know how much degrees a quadrilateral is, divided by how many spaces there is.
OpenStudy (anonymous):
okay..im confused..
OpenStudy (xapproachesinfinity):
exactly!
OpenStudy (xapproachesinfinity):
For a moment I was thinking about something else lol
OpenStudy (yanasidlinskiy):
How much degrees is there in a quadrilateral? Hahahha.
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OpenStudy (xapproachesinfinity):
hahaha sounds a good question
OpenStudy (anonymous):
360
OpenStudy (xapproachesinfinity):
let me make a guess lol, could be 360?
OpenStudy (anonymous):
so...was my answer right or wrong..
OpenStudy (xapproachesinfinity):
Correct!
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OpenStudy (yanasidlinskiy):
Lets see:) And how many angles is there?
OpenStudy (anonymous):
4
OpenStudy (yanasidlinskiy):
360/4=??
OpenStudy (anonymous):
90
OpenStudy (xapproachesinfinity):
well a quadrilateral could have angles that are greater or less than 90 but the total is still 360 degrees
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OpenStudy (yanasidlinskiy):
So now..you would get half of 90 and its 45:) So..You're correct!!!!!!!!!!!!!! Great job!!:)
OpenStudy (anonymous):
thanks since you are so good with this do you find helping me with other questions..cause im so lost
OpenStudy (anonymous):
@xapproachesinfinity
OpenStudy (xapproachesinfinity):
Yah go a ahead, I thought you were asking Yana lol
OpenStudy (anonymous):
no haha I was asking you
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OpenStudy (anonymous):
OpenStudy (xapproachesinfinity):
ok so try to find out what a is using pythagorean theorem,
that little triangle has equal sides
OpenStudy (anonymous):
How could you do that if you are only given the hypotenuse??
OpenStudy (xapproachesinfinity):
a^2 + a^2=r^2 how is this?
OpenStudy (xapproachesinfinity):
does is make sense
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OpenStudy (xapproachesinfinity):
it
OpenStudy (anonymous):
um not really.. I no that r would equal 6 when squared
OpenStudy (anonymous):
know*
OpenStudy (xapproachesinfinity):
r^2=9.2=18 right but don't forget the LHS
OpenStudy (anonymous):
oh god...so what is the answer?? What does LHS stand for?? Sorry If I am be annoying...
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OpenStudy (xapproachesinfinity):
no problem my friend we are here to learn, I you don't know something stop me and ask.
OpenStudy (xapproachesinfinity):
so LHS stands for left hand side
OpenStudy (anonymous):
a would be 9 then right? Oh okay thanks.
OpenStudy (xapproachesinfinity):
No, you a^2=9 not a
OpenStudy (xapproachesinfinity):
you are almost there continue
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OpenStudy (xapproachesinfinity):
I mean a^2=9 not a
OpenStudy (anonymous):
okay so knowing that a^2=9 what do you do next... do you plug it back into the a^2+a^2=9 equation??
OpenStudy (xapproachesinfinity):
No, now use square root of both sides you should get a=sqrt{9}
OpenStudy (xapproachesinfinity):
what is square root of 9
OpenStudy (anonymous):
3
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OpenStudy (xapproachesinfinity):
good! so... a= what
OpenStudy (anonymous):
3
OpenStudy (xapproachesinfinity):
Great job! so we found a=3 so what do we do next
OpenStudy (anonymous):
you would use the equation 1/2(r)(p)=Area.. I think
OpenStudy (xapproachesinfinity):
Now that we found a, we still need something because a is just half the length of that quadriletral
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OpenStudy (anonymous):
you need the length of a side
OpenStudy (xapproachesinfinity):
Not that equation, that's for only triangles
OpenStudy (xapproachesinfinity):
yes!
OpenStudy (xapproachesinfinity):
we found half of that length what do we do
OpenStudy (xapproachesinfinity):
now
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OpenStudy (anonymous):
we would add six again and the length would equal 12
OpenStudy (xapproachesinfinity):
no we add 3 we got 6, so the length is 6
OpenStudy (xapproachesinfinity):
one more step and done
OpenStudy (anonymous):
we would just multiply 6 by 6|dw:1406425872248:dw| and the area would be 36
OpenStudy (xapproachesinfinity):
yay! great job
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OpenStudy (xapproachesinfinity):
area= b^2, b is the length, you have done a great job
OpenStudy (anonymous):
Oh good thanks! I have one more question..that I need help with if you don't mind helping that would be great but let me open it in a new post cause I want to give you two medals!
OpenStudy (xapproachesinfinity):
I'm sorry but im running out of time, I have to go for prayer and come back. really sorry
. I'm proud of you. you're learning fast
OpenStudy (xapproachesinfinity):
I'm doing Ramadan lol, So i need to go pray in the mosque ^^
OpenStudy (anonymous):
aww okay thanks! have fun at prayer.
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